Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 28

Answer

$2\sqrt 5$

Work Step by Step

We simplify by factoring out $\sqrt 5$ and then combine the like terms as follows: $$ 6\sqrt 5-4\sqrt 5= (6-4)\sqrt 5=2\sqrt 5 .$$
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