#### Answer

$\dfrac{x+1}{x-1}$

#### Work Step by Step

Simplify by multiplying the LCD (which is $x$) to both the numerator and the denominator to obtain:
$=\dfrac{x(1+\frac{1}{x})}{x(1-\frac{1}{x})}
\\=\dfrac{x(1)+x(\frac{1}{x})}{x(1)-x(\frac{1}{x})}
\\=\dfrac{x+1}{x-1}$