Answer
$\color{blue}{2}$
Work Step by Step
The expressions are similar since they have the same denominator.
Subtract the numerators together then copy the denominator to obtain:
$=\dfrac{7x+8-(x+4)}{3x+2}
\\=\dfrac{7x+8-x-4}{3x+2}
\\=\dfrac{(7x-x)+(8-4)}{3x+2}
\\=\dfrac{6x+4}{3x+2}$
Factor out $2$ in the numerator, then cancel the common factors to obtain:
$\require{cancel}
\\=\dfrac{2(3x+2)}{3x+2}
\\=\dfrac{2\cancel{(3x+2)}}{\cancel{3x+2}}
\\=\color{blue}{2}$
