Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises - Page 54: 51



Work Step by Step

The expressions are not similar since they have different denominators. Make the expressions similar using their LCD which is $2(3)(k) = 6k$ to obtain: $=\dfrac{3\color{red}{(3)}}{2k\color{red}{(3)}}+\dfrac{5\color{red}{(2)}}{3k\color{red}{(2)}} \\=\dfrac{9}{6k}+\dfrac{10}{6k} \\=\dfrac{9+10}{6k} \\=\color{blue}{\dfrac{19}{6k}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.