## Precalculus (6th Edition)

$\color{blue}{\dfrac{5-22x}{12x^2y}}$
The expressions are not similar since they have different denominators. Make the expressions similar using their LCD which is $12x^2y$ to obtain: $=\dfrac{5}{12x^2y} - \dfrac{11\color{red}{(2x)}}{6xy\color{red}{(2x)}} \\=\dfrac{5}{12x^2y}-\dfrac{22x}{12x^2y} \\=\color{blue}{\dfrac{5-22x}{12x^2y}}$