Answer
$\dfrac{1}{31}$
Work Step by Step
tWe are given the determinant equation as: $ \begin{bmatrix} 6x& 2&0 \\1 & 5&3\\x&2&-1 \\ \end{bmatrix}=2x$
Need to simplify the given equation for $x$.
$(6x) \times [(5)(-1)-(2)(13)]-2(-1)-2(0)+x\times [(2)(3)-(5)(0)]=2x \\ -66x+2+6x=2x\\62 x=2 \\ x=\dfrac{2}{62}\\ x=\dfrac{1}{31}$
Thus, the obtained value of $x$ is equal to $\dfrac{1}{31}$.
