Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - Chapter 9 Test Prep - Review Exercises - Page 954: 39

Answer

$$-1$$

Work Step by Step

The determinant $D$ of a $ 2 \times 2$ matrix can be calculated as: $D=\begin{vmatrix} -1 & 2 & 3 \\ 4 & 0 & 3 \\5 &-1 & 2 \\ \end{vmatrix} \\=-2[(4)(2)-(3)(5)]+0+1[(-1)(3)-(3)(4)]\\=-2(8-15)+0+1[-3-12]\\=-2(8-15)-3-12\\=-1$
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