Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - Chapter 9 Test Prep - Review Exercises - Page 954: 36

Answer

$-6$

Work Step by Step

The determinant $D$ of a $ 2 \times 2$ matrix can be calculated as: $D=\left|\begin{array}{ll} A & B\\C & D \end{array}\right|=AD-BC$ The determinant $D$ of a given $ 2 \times 2$ matrix can be calculated as: $D=\left|\begin{array}{ll} -2 & 4\\ 0 & 3 \end{array}\right|=(-2)(3)-0=-6$
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