Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Chapter 8 Test Prep - Review Exercises - Page 838: 25

Answer

$${\text{58}}{\text{.6ft}}$$

Work Step by Step

$$\eqalign{ & {\text{From the triangle we have:}} \cr & B = 58.4^\circ ,\,\,\,C = 27.9^\circ ,\,\,\,a = 125{\text{ft,}}\,\,\,c = ? \cr & \cr & {\text{Calculate }}A \cr & A = {180^ \circ } - B - C \cr & A = {180^ \circ } - 58.4^\circ - 27.9^\circ \cr & A = 93.7^\circ \cr & \cr & {\text{Calculate the side }}c{\text{ using the law of sines}} \cr & \frac{c}{{\sin C}} = \frac{a}{{\sin A}} \cr & c = \frac{{a\sin C}}{{\sin A}} \cr & c = \frac{{125\sin \left( {27.9^\circ } \right)}}{{\sin \left( {93.7^\circ } \right)}} \cr & c \approx 58.6{\text{ft}} \cr & \cr & {\text{The distance from }}A{\text{ to }}B{\text{ is 58}}{\text{.6ft}} \cr} $$
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