Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Chapter 8 Test Prep - Review Exercises - Page 838: 14

Answer

$$26.52^\circ $$

Work Step by Step

$$\eqalign{ & a = {\text{14}}.{\text{8 m}},b = {\text{19}}.{\text{7 m}},c = {\text{31}}.{\text{8 m}} \cr & \cr & {\text{Find }}B,{\text{ use the law of cosines}} \cr & {b^2} = {a^2} + {c^2} - 2ac\cos B \cr & \cos B = \frac{{{a^2} + {c^2} - {b^2}}}{{2ac}} \cr & \cr & {\text{Substitute}} \cr & \cos B = \frac{{{{\left( {{\text{14}}.{\text{8}}} \right)}^2} + {{\left( {{\text{31}}.{\text{8}}} \right)}^2} - {{\left( {{\text{19}}.{\text{7}}} \right)}^2}}}{{2\left( {{\text{14}}.{\text{8}}} \right)\left( {{\text{31}}.{\text{8}}} \right)}} \cr & {\text{Use a calculator}} \cr & \cos B \approx 0.8947284549 \cr & {\text{Use the inverse cosine function}} \cr & B \approx {\cos ^{ - 1}}\left( {0.8947284549} \right) \cr & B \approx 26.52^\circ \cr} $$
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