Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Chapter 8 Test Prep - Review Exercises - Page 838: 18

Answer

$$B = 74.6^\circ ,\,\,\,C = 43.7^\circ ,\,\,\,\,c = 62{\text{m}}$$

Work Step by Step

$$\eqalign{ & A = {\text{61}}.{\text{7}}^\circ ,a = {\text{78}}.{\text{9 m}},b = {\text{86}}.{\text{4 m}} \cr & {\text{Calculate the angle }}B{\text{ using the law of sines}} \cr & \frac{{\sin B}}{b} = \frac{{\sin A}}{a} \cr & \sin B = \frac{{b\sin A}}{a} \cr & \sin B = \frac{{{\text{86}}.{\text{4}}\sin \left( {{\text{61}}.{\text{7}}^\circ } \right)}}{{{\text{78}}.{\text{9}}}} \cr & {\text{Use a calculator}} \cr & \sin B \approx 0.9641729194 \cr & {\text{Use the inverse sine function}} \cr & B \approx 74.6^\circ \cr & \cr & {\text{Calculate the angle }}C \cr & C = 180^\circ - A - B \cr & C = 180^\circ - {\text{61}}.{\text{7}}^\circ - 74.6^\circ \cr & C = 43.7^\circ \cr & \cr & {\text{Calculate the side }}c{\text{ using the law of sines}} \cr & \frac{c}{{\sin C}} = \frac{a}{{\sin A}} \cr & c = \frac{{a\sin C}}{{\sin A}} \cr & c = \frac{{{\text{78}}.{\text{9}}\sin \left( {43.7^\circ } \right)}}{{\sin \left( {{\text{61}}.{\text{7}}^\circ } \right)}} \cr & c \approx 62{\text{m}} \cr & \cr & {\text{Answer}} \cr & B = 74.6^\circ ,\,\,\,C = 43.7^\circ ,\,\,\,\,c = 62{\text{m}} \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.