Answer
$$ - \frac{1}{6} - \frac{{\sqrt 3 }}{6}i$$
Work Step by Step
$$\eqalign{
& \frac{{3\operatorname{cis} {{305}^ \circ }}}{{9\operatorname{cis} {{65}^ \circ }}} \cr
& {\text{Using the Quotient Theorem}} \cr
& = \frac{3}{9}\operatorname{cis} \left( {{{305}^ \circ } - {{65}^ \circ }} \right) \cr
& = \frac{1}{3}\operatorname{cis} \left( {{{240}^ \circ }} \right) \cr
& = \frac{1}{3}\left( {\cos {{240}^ \circ } + i\sin {{240}^ \circ }} \right) \cr
& {\text{Write in Rectangular form}} \cr
& = \frac{1}{3}\left( { - \frac{1}{2} - \frac{{\sqrt 3 }}{2}i} \right) \cr
& = - \frac{1}{6} - \frac{{\sqrt 3 }}{6}i \cr} $$
