Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.5 Trigonometric (Polar) Form of Complex Numbers: Products and Quotients - 8.5 Exercises - Page 802: 84

Answer

$$ - 6 + 6\sqrt 3 i$$

Work Step by Step

$$\eqalign{ & \frac{{24\left( {\cos {{150}^ \circ } + i\sin {{150}^ \circ }} \right)}}{{2\left( {\cos {{30}^ \circ } + i\sin {{30}^ \circ }} \right)}} \cr & {\text{Using the Quotient Theorem}} \cr & = \frac{{24}}{2}\left[ {\cos \left( {{{150}^ \circ } - {{30}^ \circ }} \right) + i\sin \left( {{{150}^ \circ } - {{30}^ \circ }} \right)} \right] \cr & {\text{Simplify}} \cr & = 12\left[ {\cos \left( {{{120}^ \circ }} \right) + i\sin \left( {{{120}^ \circ }} \right)} \right] \cr & {\text{Write in Rectangular form}} \cr & = 12\left( { - \frac{1}{2} + \frac{{\sqrt 3 }}{2}i} \right) \cr & = - 6 + 6\sqrt 3 i \cr} $$
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