Answer
$$ - 2$$
Work Step by Step
$$\eqalign{
& \frac{{10\left( {\cos {{50}^ \circ } + i\sin {{50}^ \circ }} \right)}}{{5\left( {\cos {{230}^ \circ } + i\sin {{230}^ \circ }} \right)}} \cr
& {\text{Using the Quotient Theorem}} \cr
& = \frac{{10}}{5}\left[ {\cos \left( {{{50}^ \circ } - {{230}^ \circ }} \right) + i\sin \left( {{{50}^ \circ } - {{230}^ \circ }} \right)} \right] \cr
& {\text{Simplify}} \cr
& = 2\left[ {\cos \left( { - {{180}^ \circ }} \right) + i\sin \left( { - {{180}^ \circ }} \right)} \right] \cr
& = 2\left[ {\cos \left( {{{180}^ \circ }} \right) - i\sin \left( {{{180}^ \circ }} \right)} \right] \cr
& {\text{Write in Rectangular form}} \cr
& = 2\left[ { - 1 - i\left( 0 \right)} \right] \cr
& = - 2 \cr} $$
