Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.5 Trigonometric (Polar) Form of Complex Numbers: Products and Quotients - 8.5 Exercises - Page 802: 81

Answer

$$ - \frac{{15\sqrt 2 }}{2} + \frac{{15\sqrt 2 }}{2}i$$

Work Step by Step

$$\eqalign{ & \left( {5\operatorname{cis} {{90}^ \circ }} \right)\left( {3\operatorname{cis} {{45}^ \circ }} \right) \cr & {\text{Multiply using the Product Theorem}} \cr & = \left( 5 \right)\left( 3 \right)\operatorname{cis} \left( {{{90}^ \circ } + {{45}^ \circ }} \right) \cr & {\text{Simplify}} \cr & = 15\operatorname{cis} \left( {{{135}^ \circ }} \right) \cr & = 15\left( {\cos {{135}^ \circ } + i\sin {{135}^ \circ }} \right) \cr & {\text{Write in Rectangular form}} \cr & = 15\left( { - \frac{{\sqrt 2 }}{2} + \frac{{\sqrt 2 }}{2}i} \right) \cr & = - \frac{{15\sqrt 2 }}{2} + \frac{{15\sqrt 2 }}{2}i \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.