Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.5 Trigonometric (Polar) Form of Complex Numbers: Products and Quotients - 8.5 Exercises - Page 802: 80

Answer

$$6i$$

Work Step by Step

$$\eqalign{ & \left( {\sqrt 6 \operatorname{cis} {{120}^ \circ }} \right)\left( {\sqrt 6 \operatorname{cis} \left( { - {{30}^ \circ }} \right)} \right) \cr & {\text{Multiply using the Product Theorem}} \cr & = \left( {\sqrt 6 } \right)\left( {\sqrt 6 } \right)\operatorname{cis} \left( {{{120}^ \circ } - {{30}^ \circ }} \right) \cr & {\text{Simplify}} \cr & = 6\operatorname{cis} \left( {{{90}^ \circ }} \right) \cr & = 6\left( {\cos {{90}^ \circ } + i\sin {{90}^ \circ }} \right) \cr & {\text{Write in Rectangular form}} \cr & = 6\left( {{0^ \circ } + i\left( 1 \right)} \right) \cr & = 6i \cr} $$
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