Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Summary Exercises Verifying Trigonometric Identities - Exercises - Page 696: 9


$\cot \theta -\tan \theta =\dfrac {2\cos ^{2}\theta -1}{\sin \theta \cos \theta }$

Work Step by Step

$\cot \theta -\tan \theta =\dfrac {\cos \theta }{\sin \theta }-\dfrac {\sin \theta }{\cos \theta }=\dfrac {\cos ^{2}\theta -\sin ^{2}\theta }{\sin \theta \cos \theta }=\dfrac {\cos ^{2}\theta -\left( 1-\cos ^{2}\theta \right) }{\sin \theta \cos \theta }=\dfrac {2\cos ^{2}\theta -1}{\sin \theta \cos \theta }$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.