## Precalculus (6th Edition)

Published by Pearson

# Chapter 7 - Trigonometric Identities and Equations - Summary Exercises Verifying Trigonometric Identities - Exercises: 3

#### Answer

$\tan \dfrac {x}{2}=cscx-\cot x$

#### Work Step by Step

$\tan \dfrac {x}{2}=\dfrac {\sin \dfrac {x}{2}}{\cos \dfrac {x}{2}}=\dfrac {\sqrt {\dfrac {1-\cos x}{2}}}{\sqrt {\dfrac {1+\cos x}{2}}}=\sqrt {\dfrac {1-\cos x}{1+\cos x}}=\sqrt {\dfrac {\left( 1-\cos x\right) \left( 1-\cos x\right) }{\left( 1+\cos x\right) \left( 1-\cos x\right) }}=\sqrt {\dfrac {\left( 1-\cos x\right) ^{2}}{\sin ^{2}x}}=\dfrac {1-\cos x}{\sin x}=cscx-\cot x$

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