Answer
$\dfrac {\cot s-\tan s}{\cos s+\sin s}=\dfrac {\cos s-\sin s}{\cos s\sin s}$
Work Step by Step
$\dfrac {\cot s-\tan s}{\cos s+\sin s}=\dfrac {\dfrac {\cos s}{\sin s}-\dfrac {\sin s}{\cos s}}{\cos s+\sin s}=\dfrac {\dfrac {\cos ^{2}s-\sin ^{2}s}{\cos s\sin s}}{\cos s+\sin s}=\dfrac {\left( \cos s+\sin s\right) \left( \cos s-\sin s\right) }{\cos s\sin s\left( \cos s+\sin s\right) }=\dfrac {\cos s-\sin s}{\cos s\sin s}$
