Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Summary Exercises Verifying Trigonometric Identities - Exercises: 5

Answer

$\dfrac {\sin t}{1+\cos t}=\dfrac {1-\cos t}{\sin t}$

Work Step by Step

$\dfrac {\sin t}{1+\cos t}=\dfrac {\sin t\left( 1-\cos t\right) }{\left( 1+\cos t\right) \left( 1-\cos t\right) }=\dfrac {\sin t\left( 1-\cos t\right) }{\sin ^{2}t}=\dfrac {1-\cos t}{\sin t}$
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