Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Summary Exercises Verifying Trigonometric Identities - Exercises: 7

Answer

$\sin 2\theta =\dfrac {2\tan \theta }{1+\tan ^{2}\theta }$

Work Step by Step

$\sin 2\theta =2\sin \theta \cos \theta =2\dfrac {\tan \theta }{\sqrt {1+\tan ^{2}\theta }}\times \dfrac {1}{\sqrt {1+\tan ^{2}\theta }}=\dfrac {2\tan \theta }{1+\tan ^{2}\theta }$
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