Answer
-5.729742
Work Step by Step
Converting $-80^{\circ}06'$ to decimal degrees, we get
$-80^{\circ}06'=-(80^{\circ}+\frac{6}{60}^{\circ})=-(80^{\circ}+0.1^{\circ})=-80.1^{\circ}$
$\tan(-80^{\circ}06')=\tan(-80.1^{\circ})\approx-5.729742$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions - 5.3 Exercises - Page 534: 116
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