Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions - 5.3 Exercises - Page 534: 114

Answer

1.841771

Work Step by Step

Converting $421^{\circ}30'$ to decimal degrees, we get $421^{\circ}30'=421^{\circ}+\frac{30}{60}^{\circ}=421^{\circ}+0.5^{\circ}=421.5^{\circ}$ $\tan 421^{\circ}30'=\tan 421.5^{\circ}$ $\approx1.841771$
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