Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions - 5.3 Exercises - Page 534: 115

Answer

0.740805

Work Step by Step

Converting $-312^{\circ}12'$ to decimal degrees, we get $-312^{\circ}12'=-(312^{\circ}+\frac{12}{60}^{\circ})=-(312^{\circ}+0.2^{\circ})=-312.2^{\circ}$ $\sin(-312^{\circ}12')=\sin(-312.2^{\circ})\approx0.740805$
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