Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions - 5.3 Exercises - Page 534: 112

Answer

1.776815

Work Step by Step

Converting $145^{\circ}45'$ to decimal degrees, we get $145^{\circ}45'=145^{\circ}+\frac{45}{60}^{\circ}=145^{\circ}+0.75^{\circ}=145.75^{\circ}$ $\csc 145^{\circ}45'=\csc 145.75^{\circ}$ Now, we use the reciprocal identity $\csc\theta=\frac{1}{\sin\theta}$ to simplify the expression. $\csc 145.75^{\circ}=\frac{1}{\sin 145.75^{\circ}}\approx1.776815$
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