Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions - 5.3 Exercises - Page 534: 113

Answer

15.055723

Work Step by Step

Converting $183^{\circ}48'$ to decimal degrees, we get $183^{\circ}48'=183^{\circ}+\frac{48}{60}^{\circ}=183^{\circ}+0.8^{\circ}=183.8^{\circ}$ $\cot 183^{\circ}48'=\cot 183.8^{\circ}$ Now, we use the reciprocal identity $\cot\theta=\frac{1}{\tan\theta}$ to simplify the expression. $\cot 183.8^{\circ}=\frac{1}{\tan 183.8^{\circ}}\approx15.055723$
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