Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 460: 98

Answer

(a) $ 7$ (b) $ 1$ (c) $ 2$

Work Step by Step

Given $f(x)=log_2\ x$, we have: (a) $f(2^7)=log_2\ 2^7=7$ (b) $f(2^{log_22})=log_2\ 2^{log_22}=log_22=1$ (c) $f(2^{2log_22})=log_2\ 2^{2log_22}=2log_22=2$
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