Answer
(a) $ 7$
(b) $ 1$
(c) $ 2$
Work Step by Step
Given $f(x)=log_2\ x$, we have:
(a) $f(2^7)=log_2\ 2^7=7$
(b) $f(2^{log_22})=log_2\ 2^{log_22}=log_22=1$
(c) $f(2^{2log_22})=log_2\ 2^{2log_22}=2log_22=2$
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