Answer
(a) $ 2$
(b) $ ln3$
(c) $ 2ln3$
Work Step by Step
Given $f(x)=3^x$, we have:
(a) $f(log_32)=3^{log_32}=2$
(b) $f(log_3(ln3))=3^{log_3(ln3)}=ln3$
(c) $f(log_3(2ln3))=3^{log_3(2ln3)}=2ln3$
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