Answer
$1.9376$
Work Step by Step
Use a calculator and the change-of-base theorem, $log_{\sqrt {13}}12=\frac{log12}{log\sqrt {13}}=\frac{ln12}{ln\sqrt {13}}\approx1.9376$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 460: 87
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