Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 460: 95

Answer

(a) $ 4$ (b) $ 25$ (c) $ \frac{1}{e}$

Work Step by Step

Given $g(x)=e^x$, we have: (a) $g(ln4)=e^{ln4}=4$ (b) $g(ln5^2)=e^{ln5^2}=5^2=25$ (c) $g(ln\frac{1}{e})=e^{ln\frac{1}{e}}=\frac{1}{e}$
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