Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 460: 88

Answer

$1.0932$

Work Step by Step

Use a calculator and the change-of-base theorem, $log_{\sqrt {19}}5=\frac{ln5}{ln\sqrt {19}}\approx1.0932$
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