Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 459: 71

(a) $ 2$ (b) $ 2$ (c) $ 2$ (d) $ 1$

Use the provided model equation, we have: (a) $S(100)=0.36ln(1+\frac{100}{0.36})\approx2$ (b) $S(200)=0.36ln(1+\frac{200}{0.36})\approx2$ (c) $S(150)=0.36ln(1+\frac{150}{0.36})\approx2$ (d) $S(10)=0.36ln(1+\frac{10}{0.36})\approx1$