Answer
$7^\circ F$ to $11^\circ F$
Work Step by Step
Given $T(k)=1.03k\ ln(\frac{C}{C_0})$ and $10\le k\le 16$, we have:
For $C=2C_0, k=10$, we get $T(10)=1.03(10)ln(2)\approx7^\circ F$
For $C=2C_0, k=16$, we get $T(16)=1.03(16)ln(2)\approx11^\circ F$
Thus we obtain the range of the rise in global temperature as $7^\circ F$ to $11^\circ F$
