Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 459: 74

Answer

$1.585$

Work Step by Step

Given $P_1=0.521, P_2=0.324, P_3=0.081, P_4=0.074$, use the formula given in the textbook, we have: $H=-[P_1log_2P_1+P_2log_2P_2+P_3og_2P_3+P_4log_2P_4] \\ =-(0.521log_20.521+0.324log_20.324+0.081log_20.081+0.074log_20.074)\\ \approx1.585$
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