Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 459: 73

Answer

$1$

Work Step by Step

Use the model equation given in example 9, we have $P_1=P_2=\frac{50}{100}=0.5$: $H=-[P_1log_2P_1+P_2log_2P_2]=-2(0.5)log_2(0.5)=1$
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