## Precalculus (6th Edition)

Solve for $y$: $y+2=0 \\y+2-2=0-2 \\y=-2$ This means the given equation is equivalent to $y=-2$. RECALL: The graph of the equation $y=k$ is a horizontal line whose y-intercept is $(0, k)$. Every point on the line has a y-coordinate of $k$. Thus, the graph of the equation $y=-2$ is a horizontal line and every point on the line has a y-coordinate of $-2$. This means the following points are on the line: $(-3, -2)$ and $(3. -2)$. Plot the two points above and connect them using a straight line. (Refer to the graph in the answer part above.)