## Precalculus (6th Edition)

$f(3)=-15$
To find $f(3)$, substitute 3 to $x$ in $f(x)$ to obtain: $f(x) =-2x^2+3x-6 \\f(3)=-2(3)^2+3(3)-6 \\f(3)=-2(9)+9-6 \\f(3)=-18+9-6 \\f(3)=-9-6 \\f(3)=-15$