Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises: 31


$(-\infty, 2]$

Work Step by Step

The radicand (expression inside the radical sign) of a square root is not allowed to be negative since negative real numbers do not have real number square roots. Thus, the domain of the given function can be found by setting $6-3x$ as greater than or equal to zero: $6-3x \ge 0 \\-3x \ge 0-6 \\-3x \ge -6 \\\frac{-3x}{-3} \le \frac{-6}{-3} \text{(inequality becomes $\le$ because a negative number was divided to both sides)}$ $x \le 2$ Therefore, the domain of the function is $(-\infty, 2]$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.