Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises - Page 297: 30


$(-\infty, 8) \cup (8, +\infty)$

Work Step by Step

The denominator is not allowed to be equal to zero since dividing zero to ny number is undefined. Since $8$ will make the denominator equal to zero, then the value of $x$ is not allowed to be $8$. The function is defined for all real numbers except $8$. Thus, the function's domain is: $(-\infty, 8) \cup (8, +\infty)$.
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