#### Answer

$r=\dfrac {1}{2}$

#### Work Step by Step

$r=\dfrac {a_{n+1}}{a_{n}}=\dfrac {-6}{-12}=\dfrac {-12}{-24}=\dfrac {-24}{-48}=\dfrac {1}{2}\Rightarrow -1 < r < 1$
So the sum converges

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$r=\dfrac {1}{2}$

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