Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.3 Geometric Sequences and Series - 11.3 Exercises - Page 1034: 29


$r=\dfrac {1}{5};a_{1}=125$

Work Step by Step

$\dfrac {a_{m}}{a_{n}}=r^{m-n}\Rightarrow \dfrac {a_{8}}{a_{3}}=r^{5}=\dfrac {\dfrac {1}{625}}{5}=\dfrac {1}{5^{5}}\Rightarrow r=\dfrac {1}{5};a_{3}=a_{1}\times r^{2}\Rightarrow 5=a_{1}\times \left( \dfrac {1}{5}\right) ^{2}\Rightarrow a_{1}=125$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.