#### Answer

$29511$

#### Work Step by Step

$\sum ^{9}_{n=3}3^{k}=\dfrac {a_{1}\left( r^{n}-1\right) }{r-1};a_{1}=3^{3}=27;r=3;n=9-3+1=7\Rightarrow s_{n}=\dfrac {27\times \left( 3^{7}-1\right) }{3-1}=29511$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$29511$

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