Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.3 Geometric Sequences and Series - 11.3 Exercises - Page 1034: 39

Answer

$-183$

Work Step by Step

$S_{n}=\dfrac {a_{1}\left( r^{n}-1\right) }{r-1};a_{1}=\left( -3\right) ^{1}=-3;r=\left( -3\right) \Rightarrow \sum ^{5}_{i=1}\left( -3\right) ^{i}=\dfrac {-3\left( \left( -3\right) ^{5}-1\right) }{-3-1}=-183$
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