Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.3 Geometric Sequences and Series - 11.3 Exercises: 20

Answer

$a_{5}=a_{1}\times r^{5-1}=\dfrac {9}{4}\times 2^{4}=36;$ $a_{n}=a_{1}\times r^{n-1}=\dfrac {9}{4}\times 2^{n-1}$

Work Step by Step

$a_{1}=\dfrac {a_{4}}{r^{3}}=\dfrac {18}{2^{3}}=\dfrac {9}{4};a_{5}=a_{1}\times r^{5-1}=\dfrac {9}{4}\times 2^{4}=36;a_{n}=a_{1}\times r^{n-1}=\dfrac {9}{4}\times 2^{n-1}$
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