Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 179: 97

Answer

$(-2,0)$

Work Step by Step

Step 1. Rewrite the inequality as $\frac{3x-2}{x}-4\gt0\longrightarrow \frac{3x-2-4x}{x}\gt0\longrightarrow \frac{-x-2}{x}\gt0\longrightarrow \frac{x+2}{x}\lt0$ Step 2. Identify the boundary points $x=-2,0$ and separate the number line into intervals $(-\infty, -2)$, $(-2,0)$, and $(0,\infty)$ Step 3. Use test points $x=-3,-1,1$ to get the signs of the left side of the inequality as $+,-,+$ Step 4. Based on the signs, we have the solution as $(-2,0)$
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