Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 179: 67

Answer

$\{ -239, 247\}$

Work Step by Step

Step 1. Given $(x-4)^{2/5}=9$, raise both side to the 5th power, we have $(x-4)^{2}=9^5=3^{10}$ Step 2. Take square root on both sides to get $x-4=\pm(3^5)=\pm243$ Step 3. Thus $x=-239, 247$ or in set form $\{ -239, 247\}$
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