Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 179: 58

Answer

$104.5\ ft/sec$

Work Step by Step

Step 1. Given the model equation $D = 0.1s^2 - 3s + 22$ and $D=800\ ft$, we have $0.1s^2 - 3s + 22=800\longrightarrow 0.1s^2 - 3s -778=0$ Step 2. We can identify $a=0.1, b=-3, c=-788$, thus $s=\frac{3\pm\sqrt {(-3)^2-4(0.1)(-778)}}{2(0.1)}=\frac{3\pm\sqrt {320.2}}{0.2}$ Step 3. As the speed need to be positive, choose the $+$ sign, we have $s=\frac{3+\sqrt {320.2}}{0.2}\approx104.5\ ft/sec$
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