Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 179: 63



Work Step by Step

Multiply $3x$ to both sides to obtain: \begin{array}{ccc} \\&3x(\frac{2}{x} - \frac{4}{3x})&=&3x(8+\frac{3}{x}) \\&3x(\frac{2}{x}) - 3x(\frac{4}{3x})&=&3x(8)+3x(\frac{3}{x}) \\&\frac{6x}{x} - \frac{12x}{3x}&=&24x+\frac{9x}{x} \\&6-4&=&24x+9 \\&2&=&24x+9 \\&2-9&=&24x \\&-7&=&24x \end{array} Divide $24$ to both sides of the equation to obtain: \begin{array}{ccc} &\dfrac{-7}{24} &= &\dfrac{24x}{24} \\&-\dfrac{7}{24}&=&x \end{array}
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