Answer
$3$
$ -\frac{1}{2}$
Work Step by Step
$2-\frac{5}{x}=\frac{3}{x^2}$ $x\ne0$
$\frac{2x^2-5x}{x^2}=\frac{3}{x^2}$ Find the LCD
$ 2x^2-5x=3$ multiply both sides by $x^2$
$ 2x^2-5x-3=0$ subtract 3 from both sides
$\Delta=b^2-4ac=5^2+3*2*4=49$
$\frac{-b\pm\sqrt \Delta}{2a}$
$\frac{5+\sqrt {49}}{4}=\frac{12}{4}=3$
$\frac{5-\sqrt {49}}{4}=-\frac{2}{4}=-\frac{1}{2}$
