Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 148: 69

Answer

$\{\frac{2}{5}, 1\}$

Work Step by Step

Step 1. Rewrite the equation as $\sqrt[3] {5x^2-6x+2}=\sqrt[3] {x}$ Step 2. Raise 3rd power on both sides to get: $5x^2-6x+2=x$ or $5x^2-7x+2=0$ which gives $x=\frac{2}{5}, 1$ Step 3. Check answers in the original equation: both $\{\frac{2}{5}, 1\}$ fit.
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